Use this information to answer the following 5 questions: : A city wants to know
ID: 3356886 • Letter: U
Question
Use this information to answer the following 5 questions::
A city wants to know if a new advertising campaign, to make citizens aware of the dangers of drunk driving, has been effective. They count the number of drivers who have been stopped with more alcohol in their systems than the law allows for each day of the week in the week before and the week a month after the campaign starts. The results are in this data link:
https://moodle-2017-2018.fullerton.edu/pluginfile.php/245784/question/questiontext/753331/34/1006869/CampaignA.xlsx
Assume that the number of stops of drunk drivers (before as well as after the campaign) is each normally distributed. Use the following notation:
(d): The mean of the difference in number of daily stops of drunk drivers between those days after and those days before the campaign.
We will be using 10% level of significance when conducting hypothesis testing.
Question 28
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Specify the null and alternative hypotheses using correct notations.
Select one:
a. H(0): (d)0 Versus H(a): (d)<0
b. H(0): (d) < 0 Versus H(a): (d)0
Question 29
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What is the value of the test statistic?
Select one:
a. -1.67
b. 1.44
c. 1.67
d. -1.44
Question 30
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At =0.1, what is the critical value of the test?
Select one:
a. -1.44
b. -1.94
c. 1.94
d. 1.44
Question 31
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At =0.1 and using the correct critical value from the preceding question
Select one:
a. We do not reject H(0)
b. We reject H(0) in favor of H(a)
Question 32
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What is the p-value?
Select one:
a. 0.05
b. 0.01
c. 0.07264536
d. 0.14529072
Day of Week After Before M 2 5 T 0 4 W 2 2 Th 1 4 F 8 6 S 7 14 Su 7 6Explanation / Answer
The statistical software output for this problem is:
Paired T hypothesis test:
D = 1 - 2 : Mean of the difference between After and Before
H0 : D = 0
HA : D < 0
Hypothesis test results:
Hence,
Answer - 28: H(0): (d)0 Versus H(a): (d)<0
Answer - 29: Test statistic = -1.67
Answer - 30: Critical value = -1.44
Answer - 31: Reject Ho
Answer - 32: P - value = 0.07264536
Difference Mean Std. Err. DF T-Stat P-value After - Before -2 1.1952286 6 -1.6733201 0.0726Related Questions
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