A sample of 200 elements produced a sample proportion of 0.47. The applicable Z

Question

A sample of 200 elements produced a sample proportion of 0.47. The applicable Z score used in calculating an 98% confidence interval for the population proportion is (a) 2.323 (b) 0.765 (c) 1.388 (d) 2.862 c

. In a left-tailed test of hypothesis, the sign in the alternative hypothesis is (a) not equal to () (b) greater than (>) (c) less than (<) (d) less than or equal to ()

In a test of hypothesis, the null hypothesis is that the population mean is equal to 50 and the alternative hypothesis is that the population mean is greater than 50. The test is to be made at the 1% significance level. The critical value of Z is (a) 2.07 (b) 2.33 (c) -2.58 (d) -1.96

Explanation / Answer

Answer to the question is as follows:

a. is right.
We need to find Z such that .98/2 + .5 = .99 is the cumulative area.
Z score for 98% confidence is 2.323

b. in a left tailed hypothesis this is how we represent: Mu<x
So, c) Less than (<)

c.

Mu = 50
Mu >50
At 1% significnace it has a Z value of b. 2.33

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