standard deviation of 25 pounds. a. Define the random variable X with words: b.

Question

standard deviation of 25 pounds. a. Define the random variable X with words: b. The probability of a randomly selected football player weighing more than 175 pounds is tributed with a mean of 200 pounds and a If we select 25 football players randomly and calculate the average weight, what is the c. standard error of the mean? d. If we select 25 football players randomly and calculate the average weight, what is the probability that the average weight is between 190 and 210 pounds? The number ofpatients arrived in a hospital between 1 1 am and 12 am has a Poisson distribution with a mean of 16. 3· What is the expected number and variance of the Poisson random variable with the 15 minutes interval? Expected value is variance is

Explanation / Answer

Q2)

a) X denote the weight of the footboll player

b) P(X>175)

P(Z>(175-200)/25)

P(Z>-1)

= 0.8413

c) Standard Error = 25/SQRT(25) = 5

d) P(190<X<210)

= P((190-200)/5<Z<(210-200)/5)

P(-2<Z<2)

= 0.9545

Q2) Expected value is 16/4 = 4

Variance is also 4

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