connect. QM 2241 Business Sta BUSINESS STATISTICS QM 2241 Fall 17 ter 8 Connect
ID: 3358257 • Letter: C
Question
connect. QM 2241 Business Sta BUSINESS STATISTICS QM 2241 Fall 17 ter 8 Connect Homework KQuestion 2 (of 5) value: 3.00 points In the Dep artment of Education at UR University, student records suggest that the population of students pends an average of 5 80 hours per week playing organized sports. The population's standard deviation is 3.50 hours per week. Based on a sample of 64 students, Healthy Lifestyles Incorporated (HLI) would like to apply the central limit theorem to make various estimates a. Compute the standard error of the sample mean (Round your answer to 2 decimal places.) Standard error b. What is the chance HLI will find a sample mean between 5 and 6 6 hours? (Round z and standard error values to 2 decimal places and final answer to 4 decimal places.) Chance c. Calculate the probability that the sample mean will be between 5.4 and 6 2 hours (Round z and standard error values to 2 decimal places and final answer to 4 decimal places.) Probability d. How strange would it be to obtain a sample mean greater than 7.80 hours? (Click to select)Explanation / Answer
Solution:- Given that mean = 5.80, sd = 3.50, n = 64
a. standard error = s/sqrtn = 3.50/sqrt64 = 0.4375 = 0.44(rounded)
b. P(5 < X < 6.6) = P((5 - 5.80)/0.44 < Z < (6.6 - 5.80)/0.44))
= P(-1.82 < Z < 1.82)
= P (Z < 1.82) P(Z < 1.82)
= 0.9312
c. P(5.4 < X < 6.2) = P((5.4 - 5.80)/0.44 < Z < (6.2 - 5.80)/0.44))
= P(-0.91 < Z < 0.91)
= 0.6372
d. P( X > 7.80) = P(Z > (7.80 - 5.80)/0.44)
= P(Z > 4.55)
= 1 P(Z < 4.55)
= 11
= 0
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.