A bank offers free coffee to its customers. The coffee is brewed each morning in

Question

A bank offers free coffee to its customers. The coffee is brewed each morning in a large coffee urn, and the amount brewed varies slightly. It is independent from day to day, with mean of 12 day to day is also random, with mean of 100 ounces and standard deviation of 5 ounces, and is independent of the amount brewed. 5 ounces and standard deviation of 3 ounces. The amount customers drink from What is the mean and standard deviation for the amount of coffee remaining at the end of th day? A. B. C. D. Mean-25 ounces, standard deviation = VS-3 = 1.41 ounces Mean = 25 ounces, standard deviation ,5+3 = 2.83 ounces Mean = 25 ounces, standard deviation = V52-32 = 4 ounces Mean-25 ounces, standard deviation = V52+32 = 5.83 ounces ith mean 100 and sta

Explanation / Answer

See below the calculation :

Mean reamining = Mean brewed - Mean consumed = 125-100 = 25 ounces

Stdev = sqrt( stdevbrewed^2 + stdevconsumed^2) = sqrt(5^3+3^3) = 5.83 ounces

D is right answer

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