2. A research team has developed a new medication to treat ADHD. They think that
ID: 3358871 • Letter: 2
Question
2. A research team has developed a new medication to treat ADHD. They think that their new medicine will be more effective than the current medication. The team asks local doctors to do a study in which newly diagnosed children with ADHD (n = 20) are matched with other children taking the current medication (n= 20) based on symptoms and physical attributes of the children. The research team will then test all the children after one year to determine the effectiveness of the treatments with a standardized symptom score-sheet (scores can range from 1-50).
1. What are the researcher’s independent and dependent variables?
a. Independent:
b. Dependent:
2. What are the null and alternative hypotheses (use the appropriate symbols not words)?
a. H0:
b. H1:
3. What is the appropriate test for the researcher to use?
4. Why is that statistic appropriate?
If applicable to the specific test:
5. What are the test’s assumptions?
6. What are the test’s df?
7. What is the appropriate critical value?
8. If the research obtains a test statistic of ____ , would the researcher retain or reject H0?
9. Should the researcher do any follow up tests or make any graphs/charts?
10. Interpret the findings in APA style
Explanation / Answer
ANSWER :-
We know that independent variables varies with only chance while Dependent Variable vaires when independent variable varies in our case
1)
Children's symptoms and Physical attributes depends on different kind of two medication so
a) Independent Variables : New Medication ,current medication
b) Dependent Variable : Symptoms and Physical attributes of children's
2)
H0 : (new) - current = 0
H1 : (new) - current > 0
3)
Since in this case Population standard deviation is unknown so researcher should use T-Statistics
4)
Since we have to test the difference between two means while Population Standard deviation is unknown
hence we use the T-statistics
5)
Assumptions are
1) Assume that the data coming from Normal population
2) Assume Population Variance of both the groups equal
6)
df = n1 + n2 - 2 = 20 + 20 - 2 = 38
7)
at 5% level of significance
critical value =1.686
8)
P value = P(t>1.21) = 0.12
P value > level of significance
Hence failed to reject the null hypothesis
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