The test statistic is -2.93, but I need assistance with the upper and lower boun

Question

The test statistic is -2.93, but I need assistance with the upper and lower bound for the p-value based on the t-table:

Two formulations of a certain coating, designed to inhibit corrosion, are being tested. For each of eight pipes, half the pipe is coated with formulation A and the other half is coated with formulation B. Each pipe is exposed to a salt environment for 500 hours. Afterward, the corrosion loss (in m) is measured for each formulation on each pipe with the results shown: Pipe 1 2 3 4 5 6 7 8 A 196 161 143 161 185 155 136 130 B 20311811401 17 18211621155142 Using a significance level of = 0.05, can you conclude that the mean amount of erosion differs between the two formulations? Compute the test statistic: -2.93 the upper and lower bound for the P-value based on the t-table:

Explanation / Answer

As we are doing a two tailed test here, the p-value here is computed as: Using n1 + n2 - 2 = 14 degrees of freedom,

p = 2P(t14 < -2.93 )

Getting the above from the t-distribution tables, we get:

p = 2P(t14 < -2.93 ) = 2*0.0055 = 0.0110

Therefore, the pvalue range here is given as:

0.01 < p-value < 0.025

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