The weight of a small Starbucks coffee is a normally distributed random variable

Question

The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 405 grams and a standard deviation of 21 grams. Find the weight that corresponds to each event. (Use Excel or Appendix C to calculate the z-value. Round your final answers to 2 decimal places.)

The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 405 grams and a standard deviation of 21 grams. Find the weight that corresponds to each event. (Use Excel or Appendix C to calculate the z-value. Round your final answers to 2 decimal places.)

Explanation / Answer

a) Highest 20 percent = 0.8416*21+405 = 422.67

b) Middle 60 percent

x1 = -0.8416*21+405 = 387.33

x2 = 0.8416*21+405 = 422.67

c) Highest 80 percent = -0.8416*21+405 = 387.33

d) Lowest 15 percent = -1.0364*21+405 = 383.23

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