5. Solve the following regarding probability: 5a.) Let A and B be events in a sa
ID: 3359393 • Letter: 5
Question
5. Solve the following regarding probability:
5a.)
Let A and B be events in a sample space S such that P(A) = 0.41, P(B) = 0.46 and P(A B) = 0.14. Find P(A | B).
a) 0.3415
b) 0.0217
c) 0.8913
d) 0.1609
e) 0.3043
f) None of the above.
5b.)
Let A and B be events in a sample space S such that P(A) = 21100 , P(B) = 47100 , and P(A B) = 225 . Find P(B | Ac ).
Hint: Draw a Venn Diagram to find P(Ac B).
a) 0.5949
b) 0.1013
c) 0.8298
d) 2.2381
e) 0.4937
f) None of the above.
5c.)
Suppose that A and B are independent events. If P(A) = 35 and P(B) = 25 , find P(A B).
a) 0.04
b) 1.00
c) 0.24
d) 0.10
e) 0.06
f) None of the above.
5d.)
A pair of fair dice is cast. What is the probabiliy that at least one of the numbers falling uppermost is a 1, given that the sum of the numbers falling uppermost is even?
a) 0.3667
b) 0.4545
c) 0.3056
d) 0.2778
e) 0.1389
f) None of the above.
Explanation / Answer
5a) P(A | B) =P(AnB)/P(B)=0.14/0.46=0.3043 option e
5b) P(Ac B) =P(B)- P(A B) =47/100-2/25 =39/100
P(Ac)=1-P(A)=1-21/100 =79/100
hence P(B | Ac ) = P(Ac B)/P(Ac)=(39/100)/(79/100)=39/79=0.4937
option e
5c) P(A B) =P(A)*P(B)=0.24
option C
5d)
probability sum is even =18/36
and number of events where at least one of the numbers falling uppermost is a 1 as well sum is even =5
hence probabiliy that at least one of the numbers falling uppermost is a 1, given that the sum of the numbers falling uppermost is even =(5/36)/(18/36)=5/18=0.2778
option D
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.