As part of the study on ongoing fright symptoms due to exposure to horror movies

Question

As part of the study on ongoing fright symptoms due to exposure to horror movies at a young age, the following table was presented to describe the lasting impact these movies have had during bedtime and waking life:

(a) What percent of the students have lasting waking-life symptoms? (Round your answer to two decimal places.)
%

(b) What percent of the students have both waking-life and bedtime symptoms? (Round your answer to two decimal places.)
%

(c) Test whether there is an association between waking-life and bedtime symptoms. State the null and alternative hypotheses. (Use = 0.01.)

Null Hypothesis: Options:

H0: Waking symptoms cause bedtime symptoms.H0: There is a relationship between waking and bedtime symptoms.    H0: There is no relationship between waking and bedtime symptoms.H0: Bedtime symptoms cause waking symptoms.

Alternative Hypothesis: Options

Ha: There is no relationship between waking and bedtime symptoms.Ha: Bedtime symptoms cause waking symptoms.    Ha: There is a relationship between waking and bedtime symptoms.Ha: Waking symptoms cause bedtime symptoms.

State the 2 statistic and the P-value. (Round your answers for 2 and the P-value to three decimal places.)

Conclusion:

We have enough evidence to conclude that there is a relationship

OR

We do not have enough evidence to conclude that there is a relationship

     Waking
symptoms Bedtime symptoms Yes      No Yes 35 33 No 33 18

Explanation / Answer

a)percent of the students have lasting waking-life symptoms =(35+33)/(35+33+33+18)*100=57.14%

b) percent of the students have both waking-life and bedtime symptoms=35/(35+33+33+18)*100=29.41%

c)Null Hypothesis:HoThere is no relationship between waking and bedtime symptoms

Ha: There is a relationship between waking and bedtime symptoms.

appllying chi square test of independence on above:

2 =2.085

df =(rows-1)*(column-1)=(2-1)*(2-1)=1

p value =0.1488

We do not have enough evidence to conclude that there is a relationship

Observed O yes no Total yes 35 33 68 no 33 18 51 Total 68 51 119 Expected E=rowtotal*column total/grand total yes no Total yes 38.86 29.14 68 no 29.14 21.86 51 Total 68 51 119 chi square =(O-E)^2/E yes no Total yes 0.3829 0.5105 0.893 no 0.5105 0.6807 1.191 Total 0.893 1.191 2.085

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