Wh You are an HR manager/VP for a high extrusion manufacturer. About 30 percent

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Wh
You are an HR manager/VP for a high extrusion manufacturer. About 30 percent of production shift supervisors have left the company in the last six months.The production VP has hypothesized that the reason for the turnover is supervisor salaries. At the request of the Chief Financial Officer( CFO). you have collected the weekly income date for all the production supervisors ar your company to determine if pay is poteneially causing the excess production supervisor turnover. Assuming that the weekly income for the supervisors is normally distributed with a mean of $1000 and a standard deviation of 100

1. and recalling that Z=(X-u)/e, what is the Z value of income (X) of a supervisor who earns $1100 per week?A. 0.00 B. 0.50 C. 2.00 D.1.00

2.What is the value for Z when X=$900 A. -1.00 B. 2.00 C. -1.20 D. 1.00 E. None of the above.

3. what is the z value when X=$1000 A. 1.00 B. 0.00 C. 0.50 D. X E. None of above.

Question 4 of 8 What is the probability that a production supervisor will earn less than $1,000 per week? O A. -0.50 OB. 0.00 O c. 1.00 D 0.683 E. None of the above Reset Selection Mark for Review What's This? Question 5 of 8 What is the probability that the production supervisor will earn less than $840 per week? OA. 4452 B. 0.00 c 0548 D 9452 E. None of the above Reset Selection

Explanation / Answer

1. Z = (1100-1000)/100 = 1
Correct Answer: Option (D)

2. Z = (900 - 1000)/100 = -1
Correct Answer: Option (A)

3. Z < (1000-1000)/100) = 0
Correct answer: Option (B)

4. The probabilty that a production supervisor will earn less then 1000 per week is
P(X < 1000) = P(Z < (1000-1000)/100)) = P(Z < 0) = 0.5
Correct Answer: Option (E)

5. The probabilty that a production supervisor will earn less then 840 per week is
P(X < 840) = P(Z < (840-1000)/100)) = P(Z < -1.6) = 0.0548
Correct Answer: Option (C)

6.The probabilty that a production supervisor will earn less then 1000 and greater than 840 per week is
P(840 < X < 1000) = P(Z < (1000-1000)/100)) - P(Z < (840-1000)/100)) = P(Z < 0)- P(Z < -1.6) = 0.5 - 0.0548 = 0.4452
Correct Answer: Option (B)

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