The National Health Interview Survey conducted of 33,326 adults by the U.S. Nati

Question

The National Health Interview Survey conducted of 33,326 adults by the U.S. National Center for Health Statistics in 2003 indicated that 21.4% of adults were current smokers. A similar study conducted in 1991 of 42 000 adults indicated that 25.690 were current smokers we w use the subscript T f ·t er i991 nd the bscri 2" for the year 2003. (a) Find a point estimate of the difference between the proportion of current smokers in 1991 and the proportion of current smokers in 2003. Use 3 decimal places.

Explanation / Answer

Given:- In this problem we will be use binomial probability distribution mean (np).

Because mean is nothing but the point estimate.

U.S. National Center for Helth Statistics :

2003:--

n= 33326 adults. and p=proportional adult =21.4%= 0.214

Mean1= n*p = 33326* 0.214 =7131.764

1991:--

n=42000 adults and p=25.6%= 0.256

Mean2 = n*p = 42000*0.256 = 10752

Therefore the difference between point estimate

= Mean2 - Mean1

= 10752 - 7131.764

= 3620.236

I

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