Rosenwald and Stonehill (E17) hypothesized that women\'s early postpartun differ
ID: 3359849 • Letter: R
Question
Rosenwald and Stonehill (E17) hypothesized that women's early postpartun differ from later breakdowns in that each represents the pathological resolution of a differ- ent crisis of motherhood. Table 5.24 shows, for 12 women experiencing early postpartum breakdowns and 14 experiencing late breakdowns, the number who suffered high and low levels of withdrawal. Can we conclude on the basis of these data that the two groups differ with respect to the extent of withdrawal? Determine the P value. 5.12 TABLE 5.24 Extent of withdrawal in women experiencing early and late postpartum breakdowns Extent of withdrawal High 10 Time of breakdown Low Early Late Total Source: George C. Rosenwald and Marshall W Stonehill "Farl Total 12 14 26 2 12 12Explanation / Answer
Given table data is as below MATRIX col1 col2 TOTALS row 1 10 2 12 row 2 2 12 14 TOTALS 12 14 N = 26 ------------------------------------------------------------------ calculation formula for E table matrix E-TABLE col1 col2 row 1 row1*col1/N row1*col2/N row 2 row2*col1/N row2*col2/N ------------------------------------------------------------------ expected frequecies calculated by applying E - table matrix formulae E-TABLE col1 col2 row 1 5.5385 6.4615 row 2 6.4615 7.5385 ------------------------------------------------------------------ calculate chisquare test statistic using given observed frequencies, calculated expected frequencies from above Oi Ei Oi-Ei (Oi-Ei)^2 (Oi-Ei)^2/Ei 10 5.5385 4.4615 19.905 3.5939 2 6.4615 -4.4615 19.905 3.0806 2 6.4615 -4.4615 19.905 3.0806 12 7.5385 4.4615 19.905 2.6404 ^2 o = 12.3955 ------------------------------------------------------------------ set up null vs alternative as null, Ho: no relation b/w X and Y OR X and Y are independent alternative, H1: exists a relation b/w X and Y OR X and Y are dependent level of significance, = 0.05 from standard normal table, chi square value at right tailed, ^2 /2 =3.8415 since our test is right tailed,reject Ho when ^2 o > 3.8415 we use test statistic ^2 o = (Oi-Ei)^2/Ei from the table , ^2 o = 12.3955 critical value the value of |^2 | at los 0.05 with d.f (r-1)(c-1)= ( 2 -1 ) * ( 2 - 1 ) = 1 * 1 = 1 is 3.8415 we got | ^2| =12.3955 & | ^2 | =3.8415 make decision hence value of | ^2 o | > | ^2 | and here we reject Ho ^2 p_value =0.0004 ANSWERS --------------- null, Ho: no relation b/w X and Y OR X and Y are independent alternative, H1: exists a relation b/w X and Y OR X and Y are dependent test statistic: 12.3955 critical value: 3.8415 p-value:0.0004 decision: reject Ho
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