Due Monday, November 13th 1. 2 points) The following partially completed ANOVA t
ID: 3360395 • Letter: D
Question
Explanation / Answer
Mean Square (Status)=14.49*0.0120=0.17388
Mean Square (Gender)=0.15*0.0120=0.0018
Mean Square (Interaction)=0.95*0.0120=0.0114
Sum of Square (Status)=0.17388*2=0.34776
Sum of Square (Gender)=0.0018*1=0.0018
Sum of Square (Interaction)=0.0114*2=0.0228
Sum of Square (Error)=0.0120*66=0.792
Interaction is not significant at 0.05 level
Source of Variation df Sum of Squares Mean Square F Status 2 0.34776 0.17388 14.49 Gender 1 0.0018 0.0018 0.15 Interaction 2 0.0228 0.0114 0.95 Error 66 0.792 0.012 Total 71Interaction is not significant at 0.05 level
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