The hypothesis is that owners of the top-name Blackberry and iPhone are willing
ID: 3360646 • Letter: T
Question
The hypothesis is that owners of the top-name Blackberry and iPhone are willing to pay more per month than owners of other phones. In your Word document, answer:
Group Statistics
Phone
N
Mean
Std. Deviation
Std. Error Mean
Amount
blackberry/iphone
19
96.05
19.045
4.369
other
20
61.85
15.928
3.562
Independent Samples Test
Levene’s Test for Equality of Variances
t-test for Equality of Means
F
Sig.
t
df
Sig. (2-tailed)
Mean Difference
Std. Error Difference
95% Confidence Interval of the Difference
Lower
Upper
Amount
Equal variances assumed
.002
.966
6.096
37
.000
34.203
5.611
22.834
45.571
Equal variances not assumed
6.067
35.161
.000
34.203
5.637
22.761
45.645
(10) Do the data meet the assumption of equal variances? How do you know?
(11) What is the result of the t test? Is it statistically significant at .05? (How will you need to adjust the p value in your output?) What do you conclude about the original hypothesis?
(12) What does the 95% Confidence Interval estimate show about the mean difference in dollar amounts that people in the population would pay for monthly phone service? In what way is it consistent with the result of the hypothesis test?
Group Statistics
Phone
N
Mean
Std. Deviation
Std. Error Mean
Amount
blackberry/iphone
19
96.05
19.045
4.369
other
20
61.85
15.928
3.562
Explanation / Answer
10) If you look at p value for variance test 0.966 > 0.05
So, null is not rejected and it means variances are equal.
11) p value for t test = 0 < 0.05 means that null is rejected and test is significant at 0.05 level.
So, The hypothesis is that owners of the top-name Blackberry and iPhone are willing to pay more per month than owners of other phones is true.
12) Conf interval =
22.834
45.571
As interval doesnt contain 0, null is rejected
So, The hypothesis is that owners of the top-name Blackberry and iPhone are willing to pay more per month than owners of other phones is true.
22.834
45.571
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