P(both are the same suit) ?? How do I solve this? Question 6 of 10 (1 point) Vie

Question

P(both are the same suit) ?? How do I solve this? Question 6 of 10 (1 point) View problem in a pop-up 4.3 Section Exercise 15 Ques If 2 cards are selected from a standard deck of 52 cards without replacement, find these probabilities. Check A Enter your answers as fractions or as decimals rounded to 3 decimal places. Sol Guided S Show E Ask Myn Link to T Tab Form Part 1 Both are jacks. P(both are jacks)= 0.005 Part 2 Both are diamonds. P(both are diamonds) 0.059 Part 3 out of 3 Both are the same suit. Save fo Submit As P(both are the same suit)-

Explanation / Answer

p(both are jack) = 4/52 x 3/51 = 0.005

P(both are diamonds) = 13/52 x 12/51 = 0.059

P(both are same suit) = P(both are diamonds) + P(both are clubs) + P(both are hearts) + P(both are spades)

= (13/52 x 12/51)x4

= 0.235

OR

P(both are of same suit) = P(any suit) x P(same suit as first one)

= 52/52 x 12/51

= 0.235

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