Task 2 In Task 1 you found the mean sum of a roll of two dice was 7, if you play

Question

Task 2 In Task 1 you found the mean sum of a roll of two dice was 7, if you played craps for an entire afternoon (assuming you could afford it) you would witness many throws of the dice. 1. On an average, how many times would you expect the sum of 7 to come up? you computed the average of all the sums that actually showed up on the dice that afternoon, what would you expect it to be? 2. If Another way of interpreting the theoretical mean outcome of a discrete random variable is called the expected value. In a sense, it is the average value that we would expect to get if the trials could continue indefinitely. For example, consider tossing three coins. The possible outcomes are HHH, HHT, HTH, HTT·THH, THT, TTH-TT. To find the mean number of heads that would occur we would construct the probability distribution. Number of Heads X 0 Probability P(X) Then using the formula below, multiply each possible outcome with its corresponding probability =ZX-P(X)-0.1+1.3+2.3+3.1=1.5 We know we cannot toss three coins and end up with 1.5 heads. What this means is that itf we do this say... forever, we would average 1.5 heads or in the long run, we would "expect" to have an average of 1.5 heads per toss. Therefore, our expected value is 15. Theoretical mean Expected Value

Explanation / Answer

Here as you know that mean sum of roll of two diceis 7. So, on an average 7 will show up 1 out of 6 times whenever we throw two dices. Whatever round we play, we expect 1/6times round , 7 will show up.

As expected number of all throw , the mean value shall be equal to 7

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