4. Coefficients a Model Unstandardized Coefficients Standardized Coefficients t
ID: 3362292 • Letter: 4
Question
4.
Coefficientsa
Model
Unstandardized Coefficients
Standardized Coefficients
t
Sig.
B
Std. Error
Beta
1
(Constant)
4.633
.251
18.424
.000
FA4
-.241
.050
-.434
-4.847
.000
BAL4
.571
.049
1.050
11.719
.000
a. Dependent Variable: SAT3
a. what type of statistical analysis is this for each output
b. what is each analysis testing for
c. please interpret the output for each analysis based upon what each is testing for. Also, tell me how you were able to come to this interpretation conclusion (i.e., if an analysis is testing for correlation, then which constructs are correlated with each other and how did you come to this conclusion based upon the output).
Coefficientsa
Model
Unstandardized Coefficients
Standardized Coefficients
t
Sig.
B
Std. Error
Beta
1
(Constant)
4.633
.251
18.424
.000
FA4
-.241
.050
-.434
-4.847
.000
BAL4
.571
.049
1.050
11.719
.000
a. Dependent Variable: SAT3
Explanation / Answer
This is regression question. It is not given what type of variable is sat3 , based on this we can decide if this is logisitic or linear regression.
If sat3 is continous , then we have linear regression
If sat3 is categorical(flag variable) , then we have logisitic regression
for each variable we check whether the independent variable is signficant or not
so we formulate the hypothesis as
H0 : the variable is not signficant for the model
H1 : the variable is significant for the model
we check the respective p values for each model , if the p value is less than 0.05 then we say that the model is signficant
here the p values of both FA4 and BAL4 are 0.000 , which is less than 0.05 , hence both the variables are significant
Considering this as a logistic regression
we can interpret the beta coefficients as
for every unit change in the value of FA4 the odds of SAT3 decreases by a factor of -0.434
we can interpret the beta coefficients as
for every unit change in the value of BAL4 the odds of SAT3 increases by a factor of 0.050
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