Suppose the frequencies of blood types in a particular population are as provide

Question

Suppose the frequencies of blood types in a particular population are as provided in the table at right. Blood Type A B [a.] If two individuals are drawn at random (independently) from this population, what is the probability that they both have blood type A? Suppose the evidence (event E) is that blood of type A was found at a crime scene, which matches that of the identified suspect. Consider two propositions (events): Hp : The source of the blood at the crime scene is the suspect. Hd The source of the blood at the crime scene is NOT the suspect. [b.] Consider the Prosecution's proposition: What is P(EHp) (i.e. the probability of the evidence assuming [c.] Consider the Defense's proposition: What is P(ElHd) (i.e. the probability of the evidence assuming the [d.] What is the value of the evidence E (likelihood ratio) in favor of the Prosecution? the suspect is guilty)? suspect is innocent)?

Explanation / Answer

Solution-

(a) Required probability = P(both have blood group A)

= 0.254 * 0.254

= 0.0645

(b) P(Hp) = P(Hd) = 1/2 = 0.5

and P(E|Hp)= P(E) = P(A) = 0.254 ( Since events E and Hp are independent)

(c) P(Hp) = P(Hd) = 1/2 = 0.5

and P(E|Hd)= P(E) = P(A) = 0.254 ( Since events E and Hd are independent)

(d) P(E) = 0.254

Answers

TY!

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.