2. A researcher wants to estimate the mean weight of adult chipmunks in Geauga C
ID: 3362939 • Letter: 2
Question
2. A researcher wants to estimate the mean weight of adult chipmunks in Geauga County, Ohio. 50 adult chipmunks are captured in Geauga County and weighed before being released. The sample mean weight obtained is 3.5 ounces with a sample standard deviation of .3 of an ounce. Use this information to construct a 98% confidence interval to estimate the mean weight of adult chipmunks in Geauga County. Assume chipmunk weight is normally distributed. Interpret your interval (i.e. what, exactly, does it mean in this case). Round to 4 (four) quality decimal places.))))
Use the data in Problem 2 (The chipmunk weight problem) to construct a 99% confidence interval for the variance in the weight of adult Geauga County chipmunks. Interpret your interval (i.e. what, exactly, does it mean in this case). Round to 4 (four) quality decimal places.
Explanation / Answer
2. a)
CI for 98% n 50 mean 3.5 z-value of 98% CI 2.3263 std. dev. 0.3 SE = std.dev./sqrt(n) 0.04243 ME = z*SE 0.09870 Lower Limit = Mean - ME 3.40130 Upper Limit = Mean + ME 3.59870 98% CI (3.4013 , 3.5987 )Related Questions
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