A certain tennis player makes a successful first serve 73% of the time. Assume t

Question

A certain tennis player makes a successful first serve 73% of the time. Assume that each serve is independent of the others. If she serves 8 times, w she gets a) all 8 serves in? b) exactly 3 serves in? c) at least 6 serves in? d) no more than 5 serves in? a) The probability that she gets all 8 serves in is 0.081 (Round to three decimal places as needed.). b) The probability she gets exactily 3 serves in is 0.031 (Round to three decimal places as needed.) c) The probability she gets at least 6 serves in is 0.628 (Round to three decimal places as needed.) d) The probability that there are no more than 5 serves in is 0.372 (Round to three decimal places as needed.)

Explanation / Answer

Solution:-

a) => (0.73)^8 = 0.0806 = 0.081

b) P(X = 3) = 0.0313 = 0.031

c) P( X 6) = P(X = 6) + P(X = 7) + P(X = 8)

= 0.3089 + 0.2386 + 0.0806

= 0.628

d) P(X 5) = 1 - P(X = 6) + P(X = 7) + P(X = 8)

= 1 - 0.628

= 0.372

Note: the above answers all are right(accurate).

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