show with ti 84 if possible...thank you! This Question: 1 pt 1 of 8 (0 complete)
ID: 3363362 • Letter: S
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show with ti 84 if possible...thank you!
This Question: 1 pt 1 of 8 (0 complete) This Quiz: 8 pts possible A television sports commentator wants to estimate the proportion of citizens who "follow professional football. (a) What sample size should be obtained if he wants to be within 2 The sample size is L1 (Round up to the nearest integer ) (b) What The sample size is (Round up to the nearest integer) (c) Why are the results from parts (a) and (b) so close? Complete parts (a) through (c) percentage points with 94% confidence if he uses an estimate of 52% obtained fro m a poll? sample size should be obtained if he wants to be within 2 percentage points with 94% confidence if he does not use any prior estimates? A. O B. ° C. The results are close because 0.52(1-0 52): 0.2496 is very close to 025 The results are close because the margin of error 2% is less than 5%. The results are close because the confidence 94% is close to 100%, n .. I 11 ./ :/ | E. ! (..) | More Click to select your answer(s) searchExplanation / Answer
a.
Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)
Z a/2 at 0.06 is = 1.881
Sample Proportion = 0.52
ME = 0.02
n = ( 1.881 / 0.02 )^2 * 0.52*0.48
= 2207.8125 ~ 2208
b.
Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)
Z a/2 at 0.06 is = 1.881
Sample Proportion = 0.5
ME = 0.02
n = ( 1.881 / 0.02 )^2 * 0.5*0.5
= 2211.3506 ~ 2212
c.
the results are close since the margin off error is less than 0.05
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