Assume that a procedure yields a binomial distribution with nequals=22 trials an

Question

Assume that a procedure yields a binomial distribution with nequals=22 trials and a probability of success of pequals=0.100.10. Use a binomial probability table to find the probability that the number of successes x is exactly 11. LOADING... Click on the icon to view the binomial probabilities table. Upper P left parenthesis 1 right parenthesisP(1)equals= nothing (Round to three decimal places as needed.) since the answer is 0. I need to know the decimal point value rounded off to 3 places. I have given this question several times and I keep getting an answer of zero

Explanation / Answer

We would be using binomial distribution formula as mentioned below: -

n!/x!(n-x)!*p^x*q^n-x

22!/11!11!*0.1^11*0.9^11

is the correct answer so if rounded off this would be 0

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