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Consider the following hypothesis statement using =0.10 and data from two indepe

ID: 3364386 • Letter: C

Question

Consider the following hypothesis statement using =0.10 and data from two independent samples. Assume the population variances are equal and the populations are normally distributed. Complete parts a and b

H0: 12=0

H1: 120

x1=14.5

x2=12.0

s1=2.7

s2=3.1

n1=20

n2=16

a. Calculate the appropriate test statistic and interpret the result.

The test statistic is:

(Round to two decimal places as needed.)

The critical value(s) is(are):

(Round to two decimal places as needed. Use a comma to separate answers as needed.)

Because the test statistic:

is less than the critical value,

falls within the critical values,

is greater than the critical value,

does not fall within the critical values,

do not reject

reject

the null hypothesis.

b. Identify the p-value from part a and interpret the result.

The p-value is:

(Round to three decimal places as needed.)

Interpret the result. Choose the correct answer below.

A.

Since the p-value is

not lessnot less

than the significance level,

rejectreject

the null hypothesis.

B.

Since the p-value is

lessless

than the significance level,

rejectreject

the null hypothesis.

C.

Since the p-value is

not lessnot less

than the significance level,

do not rejectt

the null hypothesis.

D.

Since the p-value is

less

than the significance level,

do not reject

the null hypothesis.

Click to select your answer(s).

Explanation / Answer

The statistical software output for this problem is:

Two sample T summary hypothesis test:
1 : Mean of Population 1
2 : Mean of Population 2
1 - 2 : Difference between two means
H0 : 1 - 2 = 0
HA : 1 - 2 0
(with pooled variances)

Hypothesis test results:

Hence,

Test statistic = 2.59

Critical values = -1.69, 1.69

Because the test statistic does not fall within the critical values, reject the null hypothesis.

p - value = 0.014

Since the p-value is less than the significance level, reject the null hypothesis.

Difference Sample Diff. Std. Err. DF T-Stat P-value 1 - 2 2.5 0.96709465 34 2.5850624 0.0142
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