A corporation randomly selects 50 salespeople and finds hat 66% who have never e

Question

A corporation randomly selects 50 salespeople and finds hat 66% who have never en a sei m provemen course ou d ke s course e did a simi tu ,1)years ago in which 60% of a random sample of 160 salespeople wanted a self-improvement course. The groups are assumed to be independent random samples. Let 1 and 2 represent the true proportion of workers who would like to attend a self-improvement course in the recent study and the past study, respectively. What is the estimated standard error of the difference between the two sample proportions? Round to three decimal places. A. 0629 O B. 0.000 O C. 0.500 OD, 0.055

Explanation / Answer

The statistical software output for this problem is:

Two sample proportion summary hypothesis test:
p1 : proportion of successes for population 1
p2 : proportion of successes for population 2
p1 - p2 : Difference in proportions
H0 : p1 - p2 = 0
HA : p1 - p2 0

Hypothesis test results:

Hence,

Estimated standard error = 0.055

Option D is correct.

Difference Count1 Total1 Count2 Total2 Sample Diff. Std. Err. Z-Stat P-value p1 - p2 99 150 96 160 0.06 0.054900937 1.0928775 0.2744

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