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Take a Test - Jeremey Erving- Google Chrome i Secure ! https://www.mathd.com/Student/PlayerTest.aspx?testld-171923383&centerwin;=yes MA120 Fall 2 Quiz: Unit 5: Quiz Time Remaining: 01:40:23 Submit Quiz This Question: 1 pt 4 of 15 (3 complete) This Quiz: 20 pts possible Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean and standard deviation . Also, use the range rule of thumb to find the minimum usual value -2 and the maximum usual value + 2 n=1415, p=2/5 (Round to one decimal place as needed) p-20- (Round to one decimal place as needed ) +2: (Round to one decimal place as needed )

Explanation / Answer

n = 1415
p = 2/5

mean = mu = np = 1415*2/5 = 566
std. dev. = sqrt(np(1-p)) = sqrt(1415 * 2/5 * 3/5) = 18.4282

mu - 2sigma = 566 - 2*18.4282 = 529.1436

mu + 2sigma = 566 + 2*18.4282 = 602.8564

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