1. The choices for problem number 18 from the book are given below. a. 0.230 b.
ID: 3364565 • Letter: 1
Question
1. The choices for problem number 18 from the book are given below.a. 0.230 b. 0.620 c. 0.557 d. 0.935 e. 0.365
2. The choices for problem number 22 from the book are given below. a. 0.730 b. 0.080 c. 0.557 d. 0.935 e. 0.705
3. The choices for problem number 30 from the book are given below. a. 0.444 b. 0.792 c. 0.313 d. 0.689 e. 0.284
4. The choices for problem number 32 from the book are given below. a. 0.604 b. 0.125 c. 0.883 d. 0.445 e. 0.421
5. The choices for problem number 34 from the book are given below. a. 0.1400 b. 0.0932 c. 0.0417 d. 0.1167 e. 0.2368
6. The choices for problem number 50 from the book are given below. a. 0.60 b. 0.20 c. 0.90 d. 0.10 e. 0.70
7. The choices for problem number 60 from the book are given below. a. 0.40 b. 0.70 c. 0.30 d. 0.45 e. 0.25
Use the following probability distribution to answer questions 8 – 10.
x [15 -10 -5 0 5 10 15] P( X = x ) 0.05 0.34 0.13 0.24 0.08 0.11 0.05
8. Find P(-10 < X < 15) a. 0.95 b. 0.40 c. -0.29 d. 0.61 e. 0.39
9. Find P(X > 0) a. 0.24 b. 0.65 c. 0.76 d. 0.48 e. 0.36
10. Find P(X < -5) a. 0.05 b. 0.39 c. 0.60 d. 0.52 e. 0.76
Explanation / Answer
8:
P(-10<X<15) = P(X =-5) + P(X=0) + P(X=5) + P(X=10) =0.13+0.24+0.08+0.11=0.56
9:
P(X>0) = P(X=5) + P(X=10) + P(X=15) = 0.08+0.11+0.05 = 0.24
10:
P(X < -5) = P(X=-15) + P(X=-10) = 0.05+0.34 = 0.39
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