The last line is (Less/greater), (reject/do not reject), (At least one of the po

Question

The last line is (Less/greater), (reject/do not reject), (At least one of the population means is different / All the population means are the same)

Thank You Quiz: Chapter 11 Quiz This Question: 1 pt This Quiz: 8 pts possible Conaider the partialy camplesed one-way ANOWA umrytable belo a) Comp ctc the remaining entrics in the table. bl How many population mean are being tested? Bctaccn Within Tolsl 36 106 6 Table of Crilical F-scores a) Comp ctc the ANOUA tbc bclou Criical Fsces for-0.05 13313 190 9164 2 193 9353 1937 3 bl There are population means being tested. 55 343 4.757 454 4387 4284 4.307 4147 4 4e60 c) What are the rypethesse for this eet? 5.117 4256 363 3 3 348d 3.?74 3.293 3230 2.179 13' H Al the means are equal H Al the means are equa OC. HN the means are equal D. Hr: Al the means are equal. 4.747 3.885 3 9 3.l06 2996 2)L3 2849 1T06 2752 H, Not all themeans re equal H1 None o the men re 667 38 4 .159 302s15 232 .ST 74 2 4543 3287 3 29 .0 02 258 25 4,451 3.902 39T 2965 2S1G 2000 2614 2545 2n4 2.to F-Round to three decimal plac 3 nsoded.) 4,414 3558 360 20cs 2723 2.661 2ST7 25LD 24S6 2.412 State the concluzlon for 0.05 44 2 vthan tha £325 3367 3072 284, 26 257, 2A8 2432356 3.32' 400 300 276 2308 243 235 20 5 4210 33& 2960 2T28 2572 2A” 2.JTS 23(5 225 1.20L 221 Click to select your arswers) PrintDone

Explanation / Answer

Ans:

a)

SS(treatments)=SS(total)-SS(error)=106-36=70

df(error)=df(total)-df(treatments)=8-2=6

MS(treatments)=70/2=35

MS(error)=36/6=6

F=35/6=5.833

b)As,df(treatments)=2

So,there 3 treatments means that 3 population means are being tested.

c)Option C is correct.

H0:All the means are equal.

Ha:Not all the means are equal.

Critical F value=FINV(0.05,2,6)=5.143

As,F=5.833 is greater than critical F value,so we reject null hypothesis and conclude that At least one of the population means is different.

SS df MS F Treatments 70 2 35 5.833 Error 36 6 6 Total 106 8

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