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Eoon 2843: Elements of Statistics (Fall 2017, Section 4) brooks phipps&11/21/17

ID: 3365393 • Letter: E

Question

Eoon 2843: Elements of Statistics (Fall 2017, Section 4) brooks phipps&11/21/17 12:48 PM Homework: H.W. 8.1 Score: 0.56 of 1 pt 3of3(3complete) Hw Score: 51.85%, 1.56 of 3 p, &) 8.1 .9-T Question Help * The manager of a paint supply store wants to estimate the actual amount of paint contained in 1-galion cans purchased from a nationally known The manufacturers specifications state that the standard deviation of the amount of paint is equal to 0.02 gallon. A random sample of 50 cans is selected, and the sample mean amount of paint per 1-galion can is 0.996 gallon. Complete parts (a) through (d) a Construct a 95%conforce interval esimato for the poplation mean amount of t included n a 1-ganon can. 99046 sus 1.00154 (Round to five decimal places as needed.) b. On the basis of these results, do you think the manager has a right to complain to the manufacturer? Why? No, because a 1g lon part can contaring exactly 1galon ofpainties within the 95% corddencontera. e Must you assume that the population amount of paint per can is normally distributed here? Explain A No, because the Central Limit Theorem aimost aways ensures that Xis normally distributed when n is large In this case, the value of n is large B Yes, because the Centrai Lint Toomamost always ensures that X·s normatydatrbad when n is largeinthis case, te value ofnissmat populatioh:s nomaly dstbuted. Yes, since noting is known abthe distrbuton of the population, it must be assumwd that No, becase the Central Limit Theorem almost always ensures that c is nomaily distributed when m is smait. In this case, the value of n is smat d.Constr ct a00% corddence nterval estrate How does ths change yo answer to part(b)? Round to five decimal places as needed) Enter your answer in the edit fields and then click Check Answer Clear All 0 fab ops lock

Explanation / Answer

For significance level 0.1, zcrit = 1.64

90% CI = Mean +/- zcrit * /sqrt(n) = 0.996 +/- 1.64*0.02/sqrt(50) = (0.99136, 1.00064)

This does not change the answer in part b as this interval also contains the value 1