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CoSecure htp// dep16812650 Shortly afher Sephember 11th 2001, a researcher wared

ID: 3365645 • Letter: C

Question

CoSecure htp// dep16812650 Shortly afher Sephember 11th 2001, a researcher wared to determine if the peeportion of temales th 28 favored war wih Irag. In a sample of 54 males, 29 favored war with Irag avored h ra was snficantly diferent from the preperton ofaored war wth Irag femaies, a) Let py represent the proportion of temales that favor the war p represent the propotion of males thor faivor the wa whac are the proeer hypones @ng: pv-Pnversus"-, py > b)What is the tes·MMste? Co the stai tic uurg mle setites sanded ) What is the P-val for the test? Give your answer to four deceal places. d) Using a 0.01 level of signficance, what condlusion should be rehe? 0 The proportion of emales that favor the war and thenof that fver th war ae gndndytcause th Pa i than . 0 The proportion offemales that favor the war and the proportion of mke, die erver th, war ave not seninly dhern tewe the tharda. O The proportion of females that favor the war and the proportion of makes h lev te r ore t signdy oe tecaivin the Pivalesreator than d.01 e) what ", the lower endpoint of 99% condence interval 6or diference ani th, , r) what is the upper endpont of a99% confdence ritereal Sor the drieence teaven the prestroffensn that faw the Type here to search

Explanation / Answer

The statistical software output for this problem is:

Two sample proportion summary hypothesis test:
p1 : proportion of successes for population 1
p2 : proportion of successes for population 2
p1 - p2 : Difference in proportions
H0 : p1 - p2 = 0
HA : p1 - p2 0

Hypothesis test results:

99% confidence interval results:

Hence,

a) Hypotheses: Option A is correct.

b) Test statistic = -1.7191

c) P - value = 0.0856

d) Option D is correct. [p - value > 0.01, not different]

e) Lower endpoint = -0.3816

f) Upper endpoint = 0.0746

Difference Count1 Total1 Count2 Total2 Sample Diff. Std. Err. Z-Stat P-value p1 - p2 28 73 29 54 -0.15347539 0.089274264 -1.7191449 0.0856
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