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Homework: 9.2- Homework Score: 0 of 1 pt 9.2.17-T Save 70f 8 (6 complete) Hw Sco

ID: 3365967 • Letter: H

Question

Homework: 9.2- Homework Score: 0 of 1 pt 9.2.17-T Save 70f 8 (6 complete) Hw Score: 18.29%, 1.46 of 8 pts Question Help it was found that 26 write with their left hands and 208 do not. In a random sample of females, it was found that 65 write with their left hands and 460 do not use a 0.01 significance level to test the daim that the rate of left-handedness among males is less than that among females. Complete pris a through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of males and the second sample to be the sample of females. What are the null and alternative hypotheses for the an hypothesis test? H1 : p1 = p2 S Identify the test statistic. (Round to two decimal places as needed.) se Enter your answer in the answer box-and then click Check Answer. Clear All Check Answer remainina

Explanation / Answer

9.2.17.

Given that,
sample one, x1 =26, n1 =208, p1= x1/n1=0.13
sample two, x2 =65, n2 =460, p2= x2/n2=0.14
null, Ho: p1 = p2
alternate, H1: p1 < p2
level of significance, = 0.01
from standard normal table,left tailed z /2 =2.33
since our test is left-tailed
reject Ho, if zo < -2.33
we use test statistic (z) = (p1-p2)/(p^q^(1/n1+1/n2))
zo =(0.125-0.14)/sqrt((0.136*0.86(1/208+1/460))
zo =-0.57
| zo | =0.57
critical value
the value of |z | at los 0.01% is 2.33
we got |zo| =0.569 & | z | =2.33
make decision
hence value of |zo | < | z | and here we do not reject Ho
p-value: left tail - Ha : ( p < -0.5688 ) = 0.28473
hence value of p0.01 < 0.28473,here we do not reject Ho
ANSWERS
---------------
null, Ho: p1 = p2
alternate, H1: p1 < p2
test statistic: -0.57
critical value: -2.33
decision: do not reject Ho
p-value: 0.28473
we do not have enough evidence to support the claim