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1.Weather Patterns Temperature patterns seem to be changing around the United St

ID: 3366006 • Letter: 1

Question

1.Weather Patterns

Temperature patterns seem to be changing around the United States. Winters seem shorter, summers seem hotter, and major storms seem more frequent. Let’s collect some data and look at what’s happening in your area.

The Weather Underground (www.wunderground.com) was created by a student/professor team at the University of Michigan and shortly thereafter became a public company providing current and historical weather data for the United States and other countries.

At the top of the Weather Underground home page you will find a box for entering the name of a city, state or country. Enter your home city or a favorite city to see the current weather conditions there. Note that at the bottom of the current conditions table, there is a box marked Historical Conditions in which you can enter a date to see statistics for any day from the past five years. For example, the data on June 1, 2002 for New Orleans, LA looks like:

Mean Temperature

83.3 o F

Max Temperature

91.4 o F

Min Temperature

75.2 o F

Cooling Degree Days

18

Experiment with this feature until you are comfortable with finding historical weather data.

Collect the Max Temperature reading for each day in YOUR home city or a city near you in each of the following time periods.

February and August of the most recent year containing both.

February and August two years previous.

February and August 4 years previous.

A. Compute 99% confidence intervals for the average daily maximum temperature in February for each of the three years in which you collected data. How do they compare?

B. Compute 99% confidence intervals for the average daily maximum temperature in August for each of the three years in which you collected data. How do they compare?

Was using website for information www.wunderground.com

Mean Temperature

83.3 o F

Max Temperature

91.4 o F

Min Temperature

75.2 o F

Cooling Degree Days

18

Explanation / Answer

we know that the confidence interval is given as

mean +- MOE

where Margin of error is given as

MOE = z*sd/sqr(n) , where n is the sample size and sd is the standard deviation

for June 2002

so n = 30, for 30 days
mean = 83.3

also , from the z table the 99% CI is 2.58

so the equation becomes

83.3 +- 2.58*sd/sqrt(30), however sd (or the dataset) is not given in the question

so just plugin the value of sd and solve for plus and minus signs to obtain the confidencen intervals as

Lower limit 83.3 - 2.58*sd/sqrt(30)
Upper limit 83.3 + 2.58*sd/sqrt(30)


Similarly , it can be done for August

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