2. (biology, wildlife conservation) /105 total points] As noted (for example) in

Question

2. (biology, wildlife conservation) /105 total points] As noted (for example) in the online reference ihipedia, the brown bear (Ursus arctos) is a species of bear distributed throughout the North ern hemisphere. The normal range of physical dimensions for height pounds, although adolescents are of course smaller. Triola and Triola a representative sa named Alt in five western U.S. states in the 1990s. Researchers study these bears in the anesthetizing them to obtain their vital measurements (as Triola and Triola note, "don't try this at home"). It's easy enough, once a bear is anesthetized, to measure its length, but it's not so easy in the back country to measure its weight. This problem is about how strong the relationship is between length (in inches) and weight in pounds) with brown bears, and how accurately you can predict the latter from the former as an estimated data-gathering tool in the wild. Figure 1 below gives descriptive and inferential analyses of this data set in JMP. (Note: you don't need to write out the full statistical model in this problem; you just need to draw upon the relevant inferential summaries an adult brown bear includes a (head-and-body length, when lying down) of 5.6 to 9.2 feet and a weight of 290 to 1,550 on data from (2006) report mple of n -54 infant and adolescent brown bears gathered by a researcher

Explanation / Answer

Solution(i)

Linear regression eq is

weight=-383.8391+9.839 length

R sq=0.7472

=74.72% varaition in weight is explained by length

RMSE=81.83

For Quadratic model

weight=-497.1143+11.03277*length+0.2962854*(length-58.8167)^2

R2=0.8282

82.82% variation in weight is exlained by length .

Good model.

R sq increased in quadratic model

RMSE =51.47

RMSE decreased from linear to quadratic.
From Residual plot we can see no pattern .

Hence Quadratic is best fit compared to linear fit.

SolutionII:

weight=-497.1143+11.03277*length+0.2962854*(length-58.8167)^2

we have length=6 feet=72 inches

Take length=72

weight=497.1143+11.03277*72+0.2962854*(72-58.8167)^2

weight=1342.96

weight=1343 pounds

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