Of the people who fished at Clearwater Park today, 24 had a fishing license, and

Question

Of the people who fished at Clearwater Park today, 24 had a fishing license, and 6 did not. Of the people who fished at Mountain View Park today, 24 had a license, and 16 did not. (No one fished at both parks.) Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license? Do not round your answer. If necessary, consult a list of formulas.) Clear Undo Help Next I don't know

Explanation / Answer

Answer will be

P( Clearwater did not have license and Mountain View had license)

(6/30)*(24/40)

= 0.2*0.6

= 0.12

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