3. An electric wire manufacturer produced the following 64 rolls of Stranded cop

Question

3. An electric wire manufacturer produced the following 64 rolls of Stranded copper wire with different lengths in fecet 624900 596400 1066400 621500 1098500 1341200 1262100 1188700 915100 1586100 1407500 679600 1140400 395400 989000 986700 770800 954100 531900 595100 457900 984400 592400 1687800 644300 1142200 796200 761900 975300 541400 565600 766400 778400 1209600 1177300 612600 1109600 1354800 612000 1695800 677900 1129800 849100 939300 1266200 543300 878800 1319000 1292800 1013100 747600 847300 1236200 1452700 684100 1471200 1230100 621600 1213100 924200 874500 661200 565100 1292800 A) Calculate the number of Classes/Bins, the Width of Each Class, the Lower and Upper limits of each Class, and obtai the Frequency for each class and state the results below: (10 POINTS)

Explanation / Answer

We need to have a small number of classes/bins in order to make an histogram readable and generate more information from it. First, let's find the range of data:

Range = Max - Min = 1695800 - 457900 = 1237900

The width of the classes have to be equal. If we keep the no. of classes/bins as 5, we can calculate the width as:

Width = Range/N = 1237900/5 = 247580

Now we know the width of each class as 247580, let's form the classes and find frequency in each class. The results are below:

Class (Lower Limit - Upper Limit) Frequency 457900-705480 20 705480-953060 13 953060-1200640 14 1200640-1448220 12 1448220-1695800 5

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