An important part of the customer service responsibilities of a cable company re

Question

An important part of the customer service responsibilities of a cable company relates to the speed with which trouble in service can be repaired. Historically, the data show that the likelihood is 0.80 that troubles in a residential service can be repaired on the same day. (Binomial distribution)

For the first five troubles reported on a given day, what is the probability that: All five will be repaired on the same day?

For the first five troubles reported on a given day, what is the probability that: Fewer than three troubles will be repaired on the same day?

For the first five troubles reported on a given day, what is the probability that: At least 3 troubles will be repaired on the same day.

For the first five troubles reported on a given day, find the mean number of troubles repaired on the same day?

HOW DO I SHOW WORK IN EXCEL USING THE BIONOM.DIST? LIKE THE EXAMPLE BELOW...

PROBLEM 4.15 cancer question Number of success 8 # of Trials 200 Probability 0.0128 Cumalitive? TRUE BINOM.IDIST 0.998781 MEAN (N of trials*P) 2.56 VARIANCE (Noftrails*P*Q) 2.527232 standard deviation(sq rt of variance) 1.589727

Explanation / Answer

Q1 the probability that: All five will be repaired on the same day

Q2 the probability that: Fewer than three troubles will be repaired on the same day

Q3 the probability that: At least 3 troubles will be repaired on the same day

Q4 the mean number of troubles repaired on the same day

Problem Q1 X=5 Q2 X<3 Q3 X>=3 Q4 Mean Number of repaired (success) 5 2 >=3 Number of Trials 5 5 5 n=5 Probability 0.8 0.8 0.8 p=0.8 Cumalitive? FALSE TRUE TRUE BINOMDIST 0.32768 0.05792 0.94208 Mean 4

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