By using the given information (green boxes), can you correct the red boxes? (re

Question

By using the given information (green boxes), can you correct the red boxes? (red box means that I am wrong)

Please use calculator or program when you solve it.

Stattes classes the aver re ex se quarter GPA as 3.92 with standard deana n 0.05. In 2 sample 1 13 st dems from h s Car lus classes the end of outer GPAis 339 ?? h sand r enat on 0.2 Lein:h repreeert the mean GP of etuderts in tsti bes atd tu ette tn Calculus teepectively. At gipificance level 0,013, lg f ere etron e Kence n ditating that Statistes 15 ?3ster thn Calolur? A) Find d and the combi stae.dard erer, SE SE01E0 B) State the Null and Abenazte Round your anner so 2 deeimal plaze Rcund your ancwer to 4 decimal places. es? Olle. >?(d > 0) ena-ail, t trst? one-tail Oleft-cail Otwo-tzil D)Find the t value of the sample Romd our we to3 decimzi plzces E) Find the Degrees or Freedom orile asmplea D. P FFid the palve of d, he diffecence in sample mesn G) Hom aoes p-rzline of the sumples comepar to 0.013?nd are the sanples sherving strong eridence oo reject Ho? Op vahe 0013, No pe DOL,No. Op-th#2 0.013, Yes. ED Based on t e anen sm es construct a 93.13 % condence uner a to est ma e 2e au erence ?n mean GP L 11.820 . . Romd 4 to 3 decimal places. of Stansacs stu ents znd Ca cans stocents d ? - ) Roud margin odee,E to 2 deal pl

Explanation / Answer

(A) SE(d-)=((sp*(1/n1 +1/n2)1/2)=0.0248 and sp2=((n1-1)s12+(n2-1)s22)/n =0.04

(D)t=21.38

statistic t=(mean1-mean2)/((sp*(1/n1 +1/n2)1/2)

(E)DF=((s12/n1+s22/n2)2)/((s12/n1)2)/(n1-1)+(s22/n2)2)/(n2-1)=119.06

(G)t(1-0.9313,119.06)=1.836

margin of error=t*SE(d-)=1.836*0.0248=0.05

t-test sample mean s s2 n (n-1)s2 statisitcs 3.92 0.05 0.0025 123 0.305 calculus 3.39 0.27 0.0729 113 8.1648 difference= 0.530 sum= 0.0754 236 8.4698 sp2= 0.04 sp= 0.19 SE 0.0248 t= 21.38 one tailed p-value= 0.0000

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