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ID: 3368298 • Letter: S
Question
show data visualizations and comment .
create data visualizations before and after the results that you would present for the following:
1)Analyze the correlation for the following data:
Orifice Diameter
Radon Released (%)
0.37
80
83
83
85
0.51
75
75
79
79
0.71
74
73
76
77
1.02
67
72
74
74
1.40
62
62
67
69
1.99
60
61
64
66
2)A company operates four machines three shifts each day. From production records, the following data on the number of breakdowns are collected:
Shift
Machines
A
B
C
D
1
41
20
12
16
2
31
11
9
14
3
15
17
16
10
Test the hypothesis (using ? = 0.05) using the Chi-Square Test that breakdowns are independent of the shift. Find the p-value for this test.
Orifice Diameter
Radon Released (%)
0.37
80
83
83
85
0.51
75
75
79
79
0.71
74
73
76
77
1.02
67
72
74
74
1.40
62
62
67
69
1.99
60
61
64
66
Explanation / Answer
Ans:
2)
Ho:Breakdowns are independent of the shift.
Ha:Breakdowns are not independent of the shift.
Expected count=row sum*column sum/overall toal
Test statistic:
Chi square score=11.65
df=(3-1)*(4-1)=6
p-value=CHIDIST(11.65,6)=0.0703
As,p-value>0.05,we fail to reject the null hypothesis and we can conclude that breakdowns are independent of the shift.
Observed count(fo) Shift/Machines A B C D Total 1 41 20 12 16 89 2 31 11 9 14 65 3 15 17 16 10 58 Total 87 48 37 40 212 Expected count(fe) Shift/Machines A B C D Total 1 36.52 20.15 15.53 16.79 89 2 26.67 14.72 11.34 12.26 65 3 23.80 13.13 10.12 10.94 58 Total 87 48 37 40 212 Chi square=(fo-fe)^2/fe Shift/Machines A B C D Total 1 0.55 0.00 0.80 0.04 1.39 2 0.70 0.94 0.48 0.25 2.37 3 3.25 1.14 3.41 0.08 7.89 Total 4.50 2.08 4.70 0.36 11.65Related Questions
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