iew History Bookmarks People Window Help Secure ttps homeworkld 4783996708questi

Question

iew History Bookmarks People Window Help Secure ttps homeworkld 4783996708questionld 26&flushed-false;&cld; 49700638centerw. Econ321 ONLINE Summer2018 morgan stoaks&1 6/19/18 3:13 PM Homework: CH 9 HW ONLINE Score: 0 of 1 pt 9.2.45 42of35 (28 complete) HW Score: 71.03%, 24.86 of 36 pts Question Heo * A doctor wants to estimate the mean HDL cholesheral of all 20- to 29-year-old females How many subjects are needed to eatimabe the me HOL cholesterol within3 points with 90% confidence assumings-143 based on earfier studies? Suppose the doctor would be content with 96% cofidenceHow does the decrease in oorfidence afflect the sample sine requined? ? ack the icon towwapartial uble of otal values oomect: 1 A 99% confidence level rquiressubijects. (Round up to the nearest subject.) nter your snewer in the anewer box and then click Check Answer 30 8 2

Explanation / Answer

Confidence Interval for the mean levels ? = x +- Z*s/sqrt(n)

Z is the value corresponding to the level of confidence

x is the sample mean and s is the sample standard deviation

n is the sample size

At 99% CI, Z = 2.58

? = x +- 2.58*s/sqrt(n)

sqrt(n) = 2.58?*s/(?-x)

Given s = 14.3 and (?-x) = 3

sqrt(n) = 12.29, n = 152

Now when we consider 95% CI, then Z will be 1.96

sqrt(n) = 1.96?*s/(?-x) = 1.96*14.3/3 =88

Let me know if you need anything else, if not please don't forget to like the answer :)

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.