Compute the Chi-square for a test of independence hypothesis. The following data
ID: 3368778 • Letter: C
Question
Compute the Chi-square for a test of independence hypothesis. The following data was collected regarding the entertainment activities of "good" people and "misguided" people. Good people watch TV 15 times a week, are on the computer chatting or gaming 12 times a week and attend social events (parties, dances, sports, etc...) 3 times a week. Misguided people watch TV 2 times a week are on the computer 5 times a week, and attend social events 8 times a week. The Chi-square value for this problem equals [AJ Carry out you answer to three decimal places Moving to the next question prevents changes to this answer Question 6 of 7 O Type here to searchExplanation / Answer
applying chi square test on above:
chi square test statistic =11.358
Observed OBS TV computer chatting social events Total good 15 12 3 30 misguided 2 5 8 15 Total 17 17 11 45 Expected Ei=?row*?column/?total TV computer chatting social events Total good 11.333 11.333 7.333 30 misguided 5.667 5.667 3.667 15 Total 17 17 11 45 chi square =(Oi-Ei)2/Ei TV computer chatting social events Total good 1.19 0.04 2.56 3.79 misguided 2.37 0.078 5.121 7.57 Total 3.56 0.12 7.68 11.358Related Questions
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