In a survey of 3148 adults, 1460 say they have started paying bills online in th

Question

In a survey of 3148 adults, 1460 say they have started paying bills online in the last year Construct a 99% confidence interval for the population proportion Interpret the results A99% conidence interval 50' the population proportion isOD Round to three decimal places as needed) Interpret your resuhs. Choose the correct answer below ? A. Wit' 99% confidence-itcan be said that the sample proportion of adults who say they have started paying bis online ithe last year is betweenthe endpoints ??. OC. of the given confidence Interval with 99% cordidence·kcan be said hatthepopulation proportion ot adds who say they have started paying bls orine inthe last year is between ho endpoints of the given confidence interval Theendpoints ofte given conidence interval show tat adults pay ble oline 99% ofthe time Cick to select your answests) lco DOLL

Explanation / Answer

Solution:- Given that n = 3148, x = 1460

p = x/n = 1460/3148 = 0.464

A 99% confidence interval for the population proportion is p +/- Z*sqrt(p*q/n)
= 0.464 +/- 2.576*sqrt(0.464*0.536/3148)
= 0.441 , 0.487

=> option B. With? 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval

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