how all work. No credit given for an answel following data shows data on oxidati

Question

how all work. No credit given for an answel following data shows data on oxidation-induction time (min) for various ts) The mercial oils. Assuming that the oxidation-induction time is normally distributed. 7 103 142 132 211 105 99 (4)Construct a 95 percent two-sided confidence interval on the mean range (the ? is not known yet). (4) Construct a 97.5 percent lower-confidence bound on the mean range (still the ?is not known yet). (5) Assuming that the population standard deviation of the time is necessary to ensure that the resulting 95% CI has a width of (at most) 50? b, C. ? 50, what sample size .307

Explanation / Answer

a)

mean = 125.5714 ,std.dev = 42.2999 , n = 7

t value at 95% = 2.447

CI = mean +/- t *(s/sqrt(n))
= 125.5714 +/- 2.447 *(42.2999/sqrt(7))
= (86.4505 , 164.6923 )

b)
mean = 125.5714 ,std.dev = 42.2999 , n = 7

t value at 95% = 2.9687

CI = mean +/- t *(s/sqrt(n))
= 125.5714 +/- 2.9687 *(42.2999/sqrt(7))
= (78.1085 , 173.0343 )

c)

ME = 50 , s = 50
t value at 95% = 2.447

ME = t *(s/sqrt(n))
50 = 2.447 *(50/sqrt(n))

n = 6

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