The following is sample information. Test the hypothesis that the treatment mean

Question

The following is sample information. Test the hypothesis that the treatment means are equal. Use the 0.05 significance level Treatment 1 Treatment 2 Treatment 3 (a) State the null hypothesis and the alternate hypothesis. Ho: | At least two of the treatment means are the same. H1; At least one treatment mean is different. (b) What is the decision rule? (Round your answer to 2 decimal places.) (Click to select: Ho if the test statistic is greater than (c&d;)Compute SST, SSE, and SS total and complete an ANOVA table. (Round SS, MS, and F values to 2 decimal places.) MS Source Treatments Error df 11.58 4.5 2 2.57 23.17 40.5 Tota 63.67 (e) State your decision regarding the null hypothesis. Do not reject Ho

Explanation / Answer

Following is the output of one way ANOVA:

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(a)

Hypotheses are:

H0: All treatmeans are same.

Ha: At least one treatment mean is different.

(b)

The critical value of F using excel function "=FINV(0.05,2,9)" is: 4.26

(e)

Since test statistics is less than critical value so we fail to reject the null hypothesis.

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Rest all answers are correct.

Anova: Single Factor SUMMARY Groups Count Sum Average Variance Treatment 1 4 17 4.25 4.25 Treatment 2 4 27 6.75 6.25 Treatment 3 4 30 7.5 3 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 23.16667 2 11.58333 2.574074 0.1306 4.256494729 Within Groups 40.5 9 4.5 Total 63.66667 11

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