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(No)(Yes) because the probability of this happening is (equal to)(less than)(gre

ID: 3369979 • Letter: #

Question

(No)(Yes) because the probability of this happening is (equal to)(less than)(greater than) 0.05

The probability that a randomly selected 3-year-old male feral cat will live to be 4 years old is 0.98168. (a) What is the probability that two randomly selected 3-year-old male feral cats will live to be 4 years old? (b) What is the probability that nine randomly selected 3-year-old male feral cats will live to be 4 years old? (c) What is the probability that at least one of nine randomly selected 3-year-old male feral cats will not live to be 4 years old? Would it be unusual if at least one of nine randomly selected 3-year-old male feral cats did not live to be 4 years old? (a) The probability that two randomly selected 3-year-old male feral cats will live to be 4 years old is Round to five decimal places as needed.) (b) The probability that nine randomly selected 3-year-old male feral cats wil live to be 4 years old is (Round to five decimal places as needed.) (c) The probability that at least one of nine randomly selected 3-year-old male feral cats will not live to be 4 years old is (Round to five decimal places as needed.) Would it be unusual if at least one of nine randomly selected 3-year-old male feral cats did not live to be 4 years old? because the probabilty of this happening is 0.05

Explanation / Answer

a) P(cat live to 4 yrs) =0.98168

p(two cats live to 4 years) = P(first cat live to 4 yrs) * P(second cat live to 4 yrs)

                                                        = 0.98168 *0.98168

                                                        =0.96370

b)

P(nine cats live to 4 yrs) = (0.98168)^9

                                             = 0.84670

c)let p be the probability that cat will not live to be 4 yrs

so p=1-0.84670 =0.1533

q=0.84670

n=9

We use binomial distribution formula

P(x>=1) =nCr p^r q^(n-r)

              =1-P(x<1)

              =1-P(x=0)

              =1-9C0 (0.1533)^0 (0.8467)^9

              =1-0.2236485

              =0.77635

No,because the probability of this happening is more(greater) than 0.05