The monthly normal temperature data from two cities are contained in the followi
ID: 3370384 • Letter: T
Question
The monthly normal temperature data from two cities are contained in the following table. Complete p City | Jan | Feb | Mar | Apr | May | Jun | Jul | Aug | Sept | Oct | Nov Dec A 61.7 61.7 658 68.8 70.5 74.4 72.7 73.3 65.6 67.6 61.3 63.7 B 126.6129.6140.71 499161.1 6691665 623151.814 213 51261 2) Compute the sample mean monthly normal temperature values for both city A and city B The mean for city A isx (Round to two decimal places as needed.) The meanfor city B is x = L? (Round tl.two decimal places as needed) 3) Compute the sample median monthly normal temperature values for both city A and city B The median for city A is M- (Type an integer or a decimal. Do not round) The median for city B is M = (Type an integer or a decimal Do not round)Explanation / Answer
Solution:-
2)
=> The mean for city A is X-bar = 67.26
mean = sum of terms/number of terms = 807.1/12 = 67.26
=> The mean for city B is X-bar = 46.02
mean = 552.2/12 = 46.02
3)
=> The median For city A is M = 66.7
Explanation: The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.
Ordering the data from least to greatest, we get:
61.3 61.7 61.7 63.7 65.6 65.8 67.6 68.8 70.5 72.7 73.3 74.4
As you can see, we do not have just one middle number but we have a pair of middle numbers, so the median is the average of these two numbers:
Median = (65.8+67.6)/2 = 66.7
=> The median for city B is M = 45.3
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