rd deviation of 4.3 inches. Suppose that these trees provide an accurate )Choose

Question

rd deviation of 4.3 inches. Suppose that these trees provide an accurate )Choose the correct Normal model for tree diameters. O A. ? ?. ??. b)what size would you expect the central 68% of all tree diameters to be? Using the 6895-99.7 rde, the central 68% ofthe tree dameters are between.inches andt inches Do not round. Type inlegers or decimals.) c) About what percent of the trees should have diameters below 1.5 inches? Using the 68.9599 7 rule, about [ % of the trees should have diameters below 1 5 nches. Do not round. Type an integer or a decimal) d) About what percent of the trees should have diameters between 14.4 and 18.7 inches? Using the 68-95-99 7 nle, about of the trees should have diameters between 14.4 and 18.7 nches (Do not round. Type an inleger or a decimal.) e) About what percent of the trees should have diameters over 18.7 inches? Using the 68-95-99.7 rule, about ??6 of the trees should have diameters over 18.7 inches. Click to select your answerts

Explanation / Answer

a) Option - C

b) According to emperical rule 68% of the data lies within one standard deviation from the mean.

10.1 - 4.3 = 5.8

10.1 + 4.3 = 14.4

68% of the tree diameters are between 5.8 inches and 14.4 inches.

c) 1.5 is two standard deviation below the mean.

According to emperical rule 95% of the data lies within two standard deviation from the mean.

So 5% of the data lies outside two standard deviation from the mean.

So 2.5% of the trees should have diameters below 1.5 inches.

d) 14.4 is one standard deviation above the mean.

so 34% of the tree lies between 10.1 and 14.4

18.7 is two standard deviation above the mean.

So 47.5% of the tree lies between 10.1 and 18.7.

Total = 34% + 47.5% = 81.5%

81.5% of the trees should have diameters between 14.4 and 18.7.

e) 18.7 is two standard deviation above the mean.

According to emperical rule 95% of the data lies within two standard deviation from the mean.

So 5% of the data lies outside two standard deviation from the mean.

So 2.5% of the trees should have diameters above 18.7 inches.

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