\" Export ason why Splnning a rouette wibeel 9 times, pig track of the occumence
ID: 3370980 • Letter: #
Question
" Export ason why Splnning a rouette wibeel 9 times, pig track of the occumences of a wieelag ruiner al"16 Adobe Exg Convert PO A) Not Hnomial the trials are not Independent B) Not bincenial thece ane more than two outoomes for eh tra Q) Net bincental: there ave too masy tials D) The peooedure seults in a binoenial diatrtbution Select POF MAT 1 he sample slze must come from a population baving a nomal 2) distribution In ander to folow normal distrbution caloulations B)40 A) 100 C) 30 D) 50 Convert To 23) The probabdity that a rndiah seed wtll gormdnte e 0.tte the probabdity that of 14023) randomly selected seeds, exactly 100 wll germinabe A) 09331 B) 0 0769 D) 00679 Change 24) The weights of cellege football playens ane sormually distributed with a mean of 200 pounds 24) nd a standaed devlato of 50 pounds. IE a college football player is randomly selected, tnd he probablity that he welighs between 170 and 220 pounds A) 0 2257 B) 0.1554 C) 00703 D) 03811 25) OH 330 randomly selected medical ehdet, 21 said that they planned to wock in a nural 25) all medical students who ceremurilty Pa d a 95% confidence Interval for the true proportion o plan to wock in a nural community Create P Send File Store File A) 00251Explanation / Answer
22)
Option C)
23)
p = 0.7 , n =140
As per binomial distribution,
P(X=r) = nCr * p^r * (1-p)^(n-r)
P(x = 100) = 140C100 * 0.7^100 * (1-0.7)^40
= 0.0679
Option D)
24)
mean = 200 , s = 50
P(170 < x < 220)
= P((170 - 200)/50) < z < (220-200)/50)
= (-0.6 < z < 0.4)
= 0.3812
Option D)
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.