Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Homework: Homework: Chapter 6- Normal Probability Distril Score: 0 of 1 pt 18 of

ID: 3371835 • Letter: H

Question

Homework: Homework: Chapter 6- Normal Probability Distril Score: 0 of 1 pt 18 of 25 (8 HW Score: 2 6.5.5 Assume that women's heights are normally distributed with a mean given by u- 63 6 in, and a (a) If 1 woman is randomly selected, find the probability that her height is less than 64 in (b) If 47 women are randomly selected, find the probability that they have a mean height less than 64 in deviation given by ?:25 (a) The (Round to four decimal places as needed) is approximately i() More Enter your answer in the answer box and then click Check Answer

Explanation / Answer

Ans:

Given that

mean=63.6

standard deviation=2.5

a)

z=(64-63.6)/2.5

z=0.16

P(z<0.16)=0.5636

b)

z=(64-63.6)/(2.5/sqrt(47))

z=1.097

P(z<1.097)=0.8637