Homework: Homework: Chapter 6- Normal Probability Distril Score: 0 of 1 pt 18 of
ID: 3371835 • Letter: H
Question
Homework: Homework: Chapter 6- Normal Probability Distril Score: 0 of 1 pt 18 of 25 (8 HW Score: 2 6.5.5 Assume that women's heights are normally distributed with a mean given by u- 63 6 in, and a (a) If 1 woman is randomly selected, find the probability that her height is less than 64 in (b) If 47 women are randomly selected, find the probability that they have a mean height less than 64 in deviation given by ?:25 (a) The (Round to four decimal places as needed) is approximately i() More Enter your answer in the answer box and then click Check AnswerExplanation / Answer
Ans:
Given that
mean=63.6
standard deviation=2.5
a)
z=(64-63.6)/2.5
z=0.16
P(z<0.16)=0.5636
b)
z=(64-63.6)/(2.5/sqrt(47))
z=1.097
P(z<1.097)=0.8637
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