Homework: Homework - Section 7.5 Score: 0 of 1 pt 7.5.15 Save 6 of 10 (5 complet
ID: 3375319 • Letter: H
Question
Homework: Homework - Section 7.5 Score: 0 of 1 pt 7.5.15 Save 6 of 10 (5 complete) HW Score: 33.89%, 3.39 of 10 pts Question Help Food and clo in are sh ed to ctims a nati al de ter ta n carton o od wil teed 9 commercial carriers transporting food and clothing are bound by the follwing constraints: e ie while ea carton ore hin will hel 4 en e ar 20 ubi 0 X 0, od ei h 4 ounds an e a se it o ox ofclot we h 20 ounas. I The The total weight per carrier cannot exceed 22,000 pounds onore than 7000 cubic The lotal volurie must be n fest. Use this infoririation to answer the followin questions How many cartons of focd and cothing shoud c sent wilh cach planc shipment to maximize he number of pcopk who can c helpe? The number of cartons of food is cartons. The numberocartansot clothing icartonsExplanation / Answer
Solution :
Let x = cartons of food
and y = cartons of clothing
=> From given data, Maximize Z = 9x + 4y
=> 20x + 5y <= 7000 ------(1)
=> 40x + 20y <= 22000 ------(2)
By Reducing these equations,
=> 4x + y = 1400 ------(3)
=> 2x + y = 1100 -------(4)
By solving (3) and (4) inequality equations ,
x = 150 , y = 800
=> The number of cartons of food is 150 cartons
The number of cartons of clothing is 800 cartons
=> the maximize Z = 9x + 4y
= 9*150 + 4*800
= 4550
=> Therefore, The maximum of 4500 people can be helped when you ship 150 cartons of food and 800 cartons of clothes.
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