7 of 10 (6 complete) core: 0 of 1o pts HW Score: 52 5%, 525 of 100 pts .2.37 EQu

Question

7 of 10 (6 complete) core: 0 of 1o pts HW Score: 52 5%, 525 of 100 pts .2.37 EQuestion Help Find the standard deviation, s, of sample data summarized in the frequency distribution table below by using the formula below, where x represents the class midpoint f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviation to the standard devlation obtained from the original list of data values, 11.1 SE n(n - 1) Interval 20-26 27-33 34-40 41-47 48-5455-61 62-68 a Frequency 29 32 Standard deviations ? (Round to one decimal place as needed) Enter your answer in the answer box and then click Check Answer Check Answe Clear All part remaining

Explanation / Answer

Ans:

Mean=4554/79=57.64557

standard deviation=sqrt(6948.08/(79-1))=9.4

interval midpoint(x) f f*x (x-57.64557)^2*f 20-26 23 2 46 2400.63 27-33 30 2 60 1528.56 34-40 37 1 37 426.24 41-47 44 2 88 372.40 48-54 51 11 561 485.80 55-61 58 29 1682 3.64 62-68 65 32 2080 1730.80 Total 79 4554 6948.08 mean= 57.64557 9.4=std. dev

Related Questions

Navigate

• Browse (All)
• Browse 7
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.